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InterviewSolution
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A current of 1.50 A was passed through an electrolytic cell containing AgNO_3 solution with inert electrodes. The weight of silver deposited was 1.50 g. How long did the current flow ? [Molar mass of Ag = 108 g mol^(-1)?, 1 F = 96500 C mol^(-1)] |
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Answer» Solution :Quantity of charge REQUIRED to DEPOSIT 108 g Ag = 96500 C Quantity of charge required to deposit 1.5 g Ag `=(96500)/108 xx 1.5 = 1340.28 C` TIME taken `=Q/l = (1340.28)/1.50 = 893.5s` |
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