A current of 1 ampere flow in a series circuit contain an electric lam

1.	A current of 1 ampere flow in a series circuit contain an electric lamp and a conductor of 5 ohm when connected to a 10 watt battery. calculate the resistance
Answer» ➠ ANSWER :- ➝ Case 1 : ➝ given :- V = 10 Total Resistance in the series = 5+R we know that → I = V/R → I = 10/(5+R) ➝ Case 2: As the resistance are in parallel series so, Total Resistance = (R¹ × R² )/( R¹+R²) → I = V/R → I = 10/5 → I = 2 Amp CURRENT in each branch = 2/2 = 1 (both of the branches have same resistance and because of it the current is DIVIDED equally.) POTENTIAL across the LAMP+ Conductor = 10V Potential across the lamp = 5 V

A current of 1 ampere flow in a series circuit contain an electric lamp and a conductor of 5 ohm when connected to a 10 watt battery. calculate the resistance

Answer»

➠ ANSWER :-

➝ Case 1 :

➝ given :-

V = 10

Total Resistance in the series = 5+R

we know that

→ I = V/R

→ I = 10/(5+R)

➝ Case 2:

As the resistance are in parallel series so,

Total Resistance = (R¹ × R² )/( R¹+R²)

→ I = V/R

→ I = 10/5

→ I = 2 Amp

CURRENT in each branch = 2/2 = 1

(both of the branches have same resistance and because of it the current is DIVIDED equally.)

POTENTIAL across the LAMP+ Conductor = 10V

Potential across the lamp = 5 V

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A current of 1 ampere flow in a series circuit contain an electric lamp and a conductor of 5 ohm when connected to a 10 watt battery. calculate the resistance​