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A current of 1 ampere flows in a series circuit containing an electric lamp and a conductor of 5 Ω when connected to a 10 V battery. Calculate the resistance of the electric lamp. Now if the resistance of 10 Ω is connected in parallel with this series combination, what change (if any) in current flowing through 5 Ω conductor and potential difference across the lamp will take place? Give reason. |
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Answer» (1) Let R be the resistance of the electric lamp. In series total resistance = 5 + R I = v/r 1 = 10/5 + R R = 5 ohm 2) V across Lamp + conductor = 10 V V across Lamp = I × R = 1 x 5 = 5 Volt |
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