A current of 1 ampere is paased for one hour between nickel electrodes in 0.5 L of 2 M Ni `(NO_(3))_(2)` solution. What will be the molarity of the solution at the end of the electrolysis?

A current of 1 ampere is paased for one hour between nickel electrodes

1.	A current of 1 ampere is paased for one hour between nickel electrodes in 0.5 L of 2 M Ni `(NO_(3))_(2)` solution. What will be the molarity of the solution at the end of the electrolysis?
Answer» The changes taking place at the electrodes in the electrolysis of `Ni(NO_(3))_(2)` solution using nickel electrodes will be as follows: At cathode: `Ni^(2+)+2etoNi` At anode: `NitoNi^(2+)+2e^(-)` thus, amount of nickel deposited on the cathode from the solution=nickel dissolved from the anode. Hence, molarity of the solution will remain unchanged at the end of the electrolysis.

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A current of 1 ampere is paased for one hour between nickel electrodes in 0.5 L of 2 M Ni `(NO_(3))_(2)` solution. What will be the molarity of the solution at the end of the electrolysis?

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