1.

A current of 10 A is applied for 1 h to 1 litre of a solution containing 1 mole of HCl. Calculate the pH of the solution at the end of this time.

Answer»

SOLUTION :At the cathode, `H_(2)` is discharged. At the anode `Cl_(2)` is preferentially discharged over `O_(2)`. Thus during ELECTROLYSIS, Hcl is lost from the solution.
Eq. of HCl lost = NUMBER of faradays used
`= (10 XX 60 xx 60)/(96500) = 0.373`
or, mole of HCl lost = 0.373.
Mole of Hcl remained/litre = 1.0 - 0.373 = 0.627.
`therefore` pH = -log(0.627) = 0.20.


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