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A current of 2 ampere is passed in a coil of radius 0.5 m and number of turns 20.The magnetic moment of the coil isA. `0.314 Am^(2)`B. `0.14A-m^(2)`C. `314A-m^(2)`D. `31.4A-m^(2)` |
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Answer» Correct Answer - D I=2A,r=0.5m,n=20,M=? M=nIA `nlpir^(2)` `20xx2xx3.14xx0.25` `=3.14Am^(2)` |
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