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A current of 4A flows through a 12V car headlight bulb for 10 minutes. How much energy transfer occurs during this time? |
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Answer» Energy = Power `xx` Time or `E = P xx t` .......(1) First of all we should calculate power P by using the current of 4A and voltage of 12 V. Now, `P = V xx I` So, `P = 12 xx 4` or, Power, `P = 48` watts `= (48)/(1000)` kilowatts Thus, Power, `P = 0.048 kW` And, Time, `t = 10` minutes `= (10)/(60)` hours `= (1)/(6)` hours Now, putting `P = 0.048 kW` and, `t = (1)/(6)` hours in equation (1), we get: `E = 0.048 xx (1)/(6)` `= 0.008 kWh` Thus, the energy transferred is 0.008 kilowatt-hour. |
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