InterviewSolution
Saved Bookmarks
| 1. |
A current of 5A flows in a resistor of 2 ohms. Calculate the energy dissipated in 300 seconds in the resistor.(a) 15kJ(b) 15000kJ(c) 1500J(d) 15JI got this question in an interview for internship.The query is from Power in portion Simple DC Networks of Basic Electrical Engineering |
|
Answer» RIGHT OPTION is (a) 15kJ For EXPLANATION I WOULD SAY: P=I^2R =5^2*2=50W. E= Pt=50*300=15000J=15kJ. |
|