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A current of 5A flows in a resistor of 2 ohms. Calculate the energy dissipated in 300 seconds in the resistor.(a) 15kJ(b) 15000kJ(c) 1500J(d) 15J |
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Answer» Right option is (a) 15kJ For explanation I would say: P=I^2R =5^2*2=50W. E= Pt=50*300=15000J=15kJ. |
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