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A current of `5A` is flowing through a 10 turns circular coil of radius `7cm`. The coil lies in x-y plane. What is the magnitude and direction of dipole moment associated with it? If this coil were placed in a uniform external magnetic field directed along the x-axis, in which plane would be coil lie in equilibrium? `pi=22//7`. |
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Answer» Here, `I=5A, N=10, r=7xx10^-2m` `M=NIA=NI(pir^2)` `=10xx5xx22/7(7xx10^-2)^2=0*77Am^2` The direction of `vecM` is perpendicular to the plane of the coil, along Z-axis. Torque on the current loop, `tau=MB sin theta` where `theta` is angle between `vecM` and `vecB`. For stable equilibrium, `tau=0 :. theta=0^@`. Hence `vecB` should be perpendicular to plane of the coil. Hence in the condition of stable equilibrium, coil will be in Y-Z plane. |
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