InterviewSolution
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InterviewSolution
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A curve is such that the mid-point of the portionof the tangent intercepted between the point where the tangent is drawn andthe point where the tangent meets the y-axis lies on the line `y=xdot`If thecurve passes through `(1,0),`then thecurve is(a)`( b ) (c)2y=( d ) x^(( e )2( f ))( g )-x (h)`(i)(b) `( j ) (k) y=( l ) x^(( m )2( n ))( o )-x (p)`(q)(c)`( d ) (e) y=x-( f ) x^(( g )2( h ))( i ) (j)`(k)(d) `( l ) (m) y=2(( n ) (o) x-( p ) x^(( q )2( r ))( s ) (t))( u )`(v)A. `2y=x^(2)-x`B. `y=x^(2)-x`C. `y=x-x^(2)`D. `y=2(x-x^(2))` |
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Answer» Correct Answer - C The point on y-axis is `(0,y-x(dy)/(dx))` According, to the given condition, `x/2=y-x/2(dy)/(dx)` or `(dy)/(dx) = 2(y/x)-1` Putting `y/x=v`, we get `x(dv)/(dx)=v-1` or `"ln"|y/x-1|="ln"|x|+c` or `1-y/x=x` [as y(1)=0] |
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