A cycle on n vertices is isomorphic to its complement. What is the value of n?(a) 5(b) 32(c) 17(d) 8This question was posed to me in quiz.My question comes from Isomorphism in Graphs in division Graphs of Discrete Mathematics

A cycle on n vertices is isomorphic to its complement. What is the val

1.	A cycle on n vertices is isomorphic to its complement. What is the value of n?(a) 5(b) 32(c) 17(d) 8This question was posed to me in quiz.My question comes from Isomorphism in Graphs in division Graphs of Discrete Mathematics
Answer» CORRECT answer is (a) 5 The best explanation: A cycle with n vertices has n edges. Number of edges in cycle = n and number of edges in its COMPLEMENT = (n(n−1)/2) – n. To be ISOMORPHISM, both graphs should have EQUAL number of edges. This gives, (n(n-1)/2) – n = n ⇒ n = 5

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