1.

A cyclic process is shown in the figure. Work done during the cyclic process ABCDA is

Answer»

160 J
150 J
600 J
900 J

Solution :Work done during cyclic process ABCDA = AREA enclosed by ABCDA
`= ((AB + CD)/(2)) xx AD`
`= ((2 +1)/(2)) xx 10^(2) = 150 J`


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