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A cyclist leaves A at 10 am and reaches B at 11 am. Starting from 10:01 am, every minute a motorcycle leaves A and moves towards B. Forty-five such motorcycles reach B by 11 am. All motorcycles have the same speed. If the cyclist had doubled his speed, how many motorcycles would have reached B by the time the cyclist reached B?1. 202. 233. 154. 22 |
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Answer» Correct Answer - Option 3 : 15 Calculation: Let the speed of a motorcycle be a and speed of cyclist be b There are 45 motorcycles reaches at 11 am ⇒ Last motorcycle reached B at 11 am ⇒ Last motorcycle left A at 10:15 am Now the speed of cyclists is doubled. ⇒ Now it will reach point B at half time ⇒ Now the last cycle left A at 10:30 am From 10:01 to 10:15, the number of motorcycles that can be left for B is 15 ∴ Maximum 15 motorcycles will reach at the time of cyclist. |
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