A cyclist on the ground goes round a ciruclar path of circumference 34.3 m in `sqrt(22)` second. The angle made by him, with the vertical, will be:-A. `45^(@)`B. `40^(@)`C. `42^(@)`D. `48^(@)`

A cyclist on the ground goes round a ciruclar path of circumference 34

1.	A cyclist on the ground goes round a ciruclar path of circumference 34.3 m in `sqrt(22)` second. The angle made by him, with the vertical, will be:-A. `45^(@)`B. `40^(@)`C. `42^(@)`D. `48^(@)`
Answer» Correct Answer - A `tan theta =(v^(2))/(rg)=(((34.3)/sqrt(22))^(2))/(((34.3)/(2pi))xx10)=1` `therefore theta=45^(@)`

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A cyclist on the ground goes round a ciruclar path of circumference 34.3 m in `sqrt(22)` second. The angle made by him, with the vertical, will be:-A. `45^(@)`B. `40^(@)`C. `42^(@)`D. `48^(@)`

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