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A cyclist starts form centre ` O` of a circular park of radius ` 1 km` and moves along the path ` OPRQO` as shown Fig. 2 (EP).15. If he maintains constant speed of ` 10 ms^(-1)`, what is his acceleration at point (R )in magnitude and direction ? .A. 10 m `s^(-2)`B. 0.1 m `s^(-2)`C. 0.01 m `s^(-2)`D. 1 m `s^(-2)` |
Answer» Correct Answer - B The acceleration at point R is towards the centre of the circle. Here, `v=10ms^(-1),r=1km=1000m` Centripetal acceleration `a_(c)=(v^(2))/(r)=((10ms^(-1))^(2))/(1000m)=0.1ms^(-2)` |
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