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A cyclist starts from centre O of a circular park of radius 1 km and moves along the path OPRQO as shown. If he maintains constant speed of 10 ms-1 . What is his acceleration at point R in magnitude & direction? |
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Answer» Centripetal acceleration, ac = \(\frac{v^2}{r}\) = \(\frac{10^2}{1000}\) = 0.1 m/s2 along RO. |
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