1.

A cylinder contains 68 g of ammonia gas at S.T.P. (1) What is the volume occupied by this gas ? (2) How many moles of ammonia are present in the cylinder ? (3) How many molecules of ammonia are present in the cylinder ? [N-14, H-1].

Answer»

Molecular weight of NH3 = (14 + 3 x 1) = 17

(1) At S.T.P., 17 g of ammonia occupies 22.4 l 

.'. Volume occupied by 68 g of ammonia 

= 22.4 x 68/17 = 89.6 l

(2) At S.T.P., 17 g of ammonia contains 1 mole 

78 g of ammonia contains = 1 x 68/17 = 4 moles

(3) Number of molecules = No. of moles x NA 

= 4 x 6.023 x 1023 

= 24.092 x 1023



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