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A cylinder contains 68 g of ammonia gas at S.T.P. (1) What is the volume occupied by this gas ? (2) How many moles of ammonia are present in the cylinder ? (3) How many molecules of ammonia are present in the cylinder ? [N-14, H-1]. |
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Answer» Molecular weight of NH3 = (14 + 3 x 1) = 17 (1) At S.T.P., 17 g of ammonia occupies 22.4 l .'. Volume occupied by 68 g of ammonia = 22.4 x 68/17 = 89.6 l (2) At S.T.P., 17 g of ammonia contains 1 mole 78 g of ammonia contains = 1 x 68/17 = 4 moles (3) Number of molecules = No. of moles x NA = 4 x 6.023 x 1023 = 24.092 x 1023 |
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