A cylinder of length 1.5 m and diameter 4 cm is fixed at one end. A tangential force of 4 xx 10^(5) N is applied at the other end. If the rigidity modulus of the cylinder is 6 xx 10^(10) Nm^(-2) then, calculate the twist produce in the cylinder.

A cylinder of length 1.5 m and diameter 4 cm is fixed at one end. A ta

1.	A cylinder of length 1.5 m and diameter 4 cm is fixed at one end. A tangential force of 4 xx 10^(5) N is applied at the other end. If the rigidity modulus of the cylinder is 6 xx 10^(10) Nm^(-2) then, calculate the twist produce in the cylinder.
Answer» Solution :Torsion of a cylinder `tau = (pi eta r^4 phi)/(2l)` Twist produced in the cylinder `phi = (tau xx (2l))/(pi eta r^4) = ((F xx l) xx (2l))/(pi eta r^4)` `= (4 xx 10^5 xx 2 xx (1.5)^2)/(3.14 xx 6 xx 10^(10) xx (2 xx 10^(-2))^(4)) = (18 xx 10^(5))/(3.01 xx 10^(-6) xx 10^(10))` `phi = 59.80`