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A cylinder of mass 10 kg is rolling perfectly on a plane of inclination 30°. find the force of friction between the cylinder are the surface of inclined plane. (μ = \(\frac{1}{3}\)) |
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Answer» Using, f = μmgcos θ, We get \(f=\frac{1}{3}\times 10 \times 9.8 \times cos\, 30°\) \(=\frac{1}{3}\times 10 \times 9.8 \times \frac{√3}{2}\) = 28.25 N |
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