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A cylinder tank of base area A has a small hole of areal a at the bottom. At time `t=0`, a tap starts to supply water into the tank at a constant rate `alpha m^(3)//s`. (a) What is the maximum level of water `h_(max)`in the tank? (b) find the time when level of water becomes `h(lt h_(max))`.A. `alpha^(2)/(2ga^(2))`B. `alpha/(2ga)`C. `(a)/(2galpha)`D. `(a^(2))/(2galpha^(2))` |
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Answer» Correct Answer - A `alpha=av=asqrt(2gh_(max)` |
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