A cylindrical block floats verticallyin a liquid of density (rho1 )kept in a container such that the fraction of volume of the cylinder inside the liquid is x1 . Then some amount of another immiscible liquid of density( rho2)((rho1>rho2) is added to the liquid in the container so that the cylinder now floats just fully immersed in the liquid with x2 fraction of volume of the cylinder inside the liquid of density rho1. The ratio rho1/ rho2.A) 1-x2/ x1-x2B) 1-x1/x1+x2C) x1-x2/x1 + x2

A cylindrical block floats verticallyin a liquid of density (rho1

1.	A cylindrical block floats verticallyin a liquid of density (rho1 )kept in a container such that the fraction of volume of the cylinder inside the liquid is x1 . Then some amount of another immiscible liquid of density( rho2)((rho1>rho2) is added to the liquid in the container so that the cylinder now floats just fully immersed in the liquid with x2 fraction of volume of the cylinder inside the liquid of density rho1. The ratio rho1/ rho2.A) 1-x2/ x1-x2B) 1-x1/x1+x2C) x1-x2/x1 + x2
Answer» Hints Considering Rho=p, M= mass of the cylinder, V= volume of the cylinder. g= acceleration due to gravity. 1st condition of floatation Mg = Vx₁p₁g 2nd condition of floatation Mg =Vx₂p₁g+V(1-x₂)p₂g Comparing these two equations we get x₁p₁=x₂p₁+(1-x₂)p₂ p₁/p₂=(1-x₂)/(x₁-x₂) Option ( A ) is accepted

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