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A cylindrical ring is rolling without slipping. The ration of rotational and translational kinetic energies isA. `0.25`B. 0.5C. 1D. 1.5

Answer» Correct Answer - C
`KE_("translational")=(1)/(2)mv^(2)`
`KE_("rotational")=(1)/(2)l omega^(2)`
`=(1)/(2)(mr^(2))omega^(2)=(1)/(2)mv^(2)`
`(KE_("tans"))/(KE_("rot"))=1`.


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