A cylindrical rod having temperature T_(1) and T_(2) at its end. The rate of flow of heat is Q_(1)("Cal")/(s) If all linear dimensions are doubled keeping temperature constant, then the rate of flow of heat Q_(2) in ("Cal")/(s) will be. . . . . . . .

A cylindrical rod having temperature T_(1) and T_(2) at its end. The r

1.	A cylindrical rod having temperature T_(1) and T_(2) at its end. The rate of flow of heat is Q_(1)("Cal")/(s) If all linear dimensions are doubled keeping temperature constant, then the rate of flow of heat Q_(2) in ("Cal")/(s) will be. . . . . . . .
Answer» `(Q_(1))/(4)` `(Q_(1))/(2)` `2Q_(1)` `4Q_(1)` Solution :`H_(1)=KA_(1)((T_(1)-T_(2))/(L_(1)))` `H_(2)=KA_(2)((T_(1)-T_(2))/(L_(2)))` `:.(H_(1))/(H_(2))=(A_(1))/(A_(2))((L_(2))/(L_(1)))` `=((pid_(1)^(2))/(4))/((pid_(2)^(2))/(4))*(L_(2))/(L_(1))` `=(d_(1)^(2))/(d_(2)^(2))xx(L_(2))/(L_(1))` `:.(Q_(1))/(Q_(2))=(d_(1)^(2))/((2d_(1))^(2))xx(2L_(1))/(L_(1))` `=1/4xx2` `=1/2` `:.Q_(2)=2Q_(1)`