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A cylindrical tube of uniform cross-sectional area A is fitted with two air tight frictionless postion. The pistons are connected to each other by a metallic wirte. Initially the pressure of the gas is p_(o) and temperature is T_(o), atmospheric pressure is also p_(o) Now the temperature of the gas is increased to 2T_(0), the tension in the wire will be |
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Answer» `2p_(o)A` V= constant  `therefore propTi.e.,` PRESSURE will be doubled, temperature is doubled `therefore""p=2p_(o)` Now let F be the tension in the wire. Then equilibrium of any one piston gives. `F=(p-p_(o))A=(2p_(o)-p_(o))A=p_(o)A` |
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