1.

A cylindrical vessel contains a liquid of density rho upto a heighth The liquid is closed by a piston of mass m and area of cross-section A. There is a small hole at the bottom of the vessel. Find the speed with which the liquid comes out of the hole

Answer»

Solution :APPLYING Bernoulli.s THEOREM at 1 and 2, DIFFERENCE in pressure energy between 1 and 2 = difference in KINETIC energy between 1 and 2

or `rhogh+(mg)/(A)=(1)/(2)rhov^(2)` or `v=sqrt(2gh+(2MG)/(rhoA))=sqrt(2(gh+(mg)/(rhoA)))`


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