InterviewSolution
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InterviewSolution
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A cylindrical vessel of height 50 cm is filled with water and rests on a table. A small hole is made at the height h from the bottom of the vessel so that the water jet could hit the table surface at a maximum distance x_(max) from the vessel as shown in the figure. The value of x_(max)will be (Neglect the viscosity of water.) |
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Answer» 15 cm  The given situation is shown in the figure. Range (MAXIMUM distance) is given by ` x = 2 SQRT(h (H - h) )`....(i) x will be maximum only when ` (dx)/(dh) = 0` `2.1 [h(-I) + (H - h)I] = 0` ` 2 sqrt(h (H - h) ) - h + (H - h ) = 0` ` H - 2h = 0` ` therefore h = (II)/(2)` Hence , x will be maximum, when ` h = H/2` ` therefore ` From Eqs. (i) we get ` x_(max) = 2 sqrt( H/2 ( H -H/2) )` ` = 2 sqrt( H/2. H/2) = H` ` x_(max) = 50 cm ` |
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