1.

a Δ ABC, if3<A = 42B = 62C, calculate the angles.

Answer»

angle A = x then angle B = 3x/4 and angle C =x/2

Sum of all angles of triangle = 180 degrees

=>x+3x/4+x/2 = 180

=> (4x+3x+2x)/4 =180

=>9x = 720 => x = 80 degrees

angle A = x = 80 degreesangle B =3x/4 = 60 degreesangle C =x/2 = 40 degrees=> 9x =720 => x =80



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