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A dancer spins about himself with an angular speed `omega`, with his arms extended. When he draws his hands in, his moment of inertia reduces by 40% . Then his angular velocity would beA. `3omega//4`B. `4omega//5`C. `5omega//4`D. `5omega//3` |
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Answer» Correct Answer - D `w_(2)=(I omega xx 100)/(60I)=(5omega)/(3)`. |
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