1.

A daniell cell is set up by dipping a zinc rod weighing 100 g in 1 litre of 1.0 M CuSO_(4) solution. How long would the cell run if it delivers a steady current of 1.0 ampere? (Atomic masses Cu=63.5,Zn=65)

Answer»

82.47 hrs
53.61 hrs
41.23 hrs
26.80 hrs

Solution :1L of 1.0 M `CuSO_(4)` solution CONTAINS `CU^(2+)=1` mole
`100" g Zn"=(100)/(65)` mole
THUS, in the cell reaction `Zn+Cu^(2+)toZn^(2+)+Cu,Cu^(2+)` ions are the limiting reagent. The cell will run till all the `Cu^(2+)` ions are deposited, i.e., 1 mole of Cu is deposited. quantity of electricity requried for DEPOSITION of 1 mole of Cu=2F
Time, `t=(2xx96500C)/(1A)=2xx96500s`
`=(2xx96500)/(3600)hr=53.61hr`


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