A daniell cell is set up by dipping a zinc rod weighing 100 g in 1 litre of 1.0 M `CuSO_(4)` solution. How long would the cell run if it delivers a steady current of 1.0 ampere? (Atomic masses Cu=63.5,Zn=65)A. 82.47 hrsB. 53.61 hrsC. 41.23 hrsD. 26.80 hrs

A daniell cell is set up by dipping a zinc rod weighing 100 g in 1 lit

1.	A daniell cell is set up by dipping a zinc rod weighing 100 g in 1 litre of 1.0 M `CuSO_(4)` solution. How long would the cell run if it delivers a steady current of 1.0 ampere? (Atomic masses Cu=63.5,Zn=65)A. 82.47 hrsB. 53.61 hrsC. 41.23 hrsD. 26.80 hrs
Answer» Correct Answer - B 1L of 1.0 M `CuSO_(4)` solution contains `Cu^(2+)=1` mole `100" g Zn"=(100)/(65)` mole thus, in the cell reaction `Zn+Cu^(2+)toZn^(2+)+Cu,Cu^(2+)` ions are the limiting reagent. The cell will run till all the `Cu^(2+)` ions are deposited, i.e., 1 mole of Cu is deposited. quantity of electricity requried for deposition of 1 mole of Cu=2F Time, `t=(2xx96500C)/(1A)=2xx96500s` `=(2xx96500)/(3600)hr=53.61hr`

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A daniell cell is set up by dipping a zinc rod weighing 100 g in 1 litre of 1.0 M `CuSO_(4)` solution. How long would the cell run if it delivers a steady current of 1.0 ampere? (Atomic masses Cu=63.5,Zn=65)A. 82.47 hrsB. 53.61 hrsC. 41.23 hrsD. 26.80 hrs

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