InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
(a) Define the equilibrium constant.(b) For the general reaction:aA(g) + bB(g) ⇌ cC(g) + dD(g)Derive the relationship between Kp and Kc. |
|
|
Answer» (a) Equilibrium constant: It is the ratio of the rate constants of forward reaction to that of backward reaction. (b) For the general reaction, aA(g) + bB(g) ⇌ cC(g) + dD(g) Equilibrium constant Kc = \(\frac{[C]^c[D]^d}{[A]^a[B]^b}\) Kp = \(\frac{[P_C]^c[P_D]^d}{[P_A]^a[P_B]^b}\) = \(\frac{[C]^c[D]^d\,(RT)^{c+d}}{[A]^a[B]^b\,(RT)^{(a+b)}}\) = \(\frac{[C]^c[D]^d}{[A]^a[B]^b}\)(RT)(c+d)-(a+b) = \(\frac{[C]^c[D]^d}{[A]^a[B]^b}\) (RT)Δn
|
||