InterviewSolution
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InterviewSolution
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(a) Define the following terms : (i) Mole fraction (ii) Ideal solution (b) `15.0`g of an unknown molecular material is dissolved in 450g of water . The resulting solution freezes at `-0.34^(@)C` . What is the molar mass of the material ? `(K_(f)` for water = `1.86` K kg `mol^(-1))` |
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Answer» (b) `Delta`mix H = 0 `Delta`mix V = 0 `DeltaT_(f) = K_(f)X` molality `DeltaT_(f) = (1.86 xx 15.0 xx 1000)/(M xx 450)` `M = (1.86 xx 150 xx 1000)/(0.34 xx 450)` `M = 182.3` gm `mol^(-1)`. |
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