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A deuteron (the nucleus of an isotope of hydrogen) has a mass of `3.34 xx 10^-27` kg and a charge of `+e`. The deuteron travels in a circular path with a radius of `6.96 mm` in a magnetic field with magnitude `2.50 T`.(a) Find the speed of the deuteron. (b) Find the time required for it to make half of a revolution. (c) Through what potential difference would the deuteron have to be accelerated to acquire this speed? |
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Answer» Correct Answer - B a. `r=(mv)/(Bq)impliesv=(Bqr)/m` b. `t=T/2=(pim)/(Bq)` c. `r=sqrt((2qVm))/(Bq)` `:. V=(r^2B^2q^2)/(2qm) =(r^2B^2q)/(2m)` |
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