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A charged particle of unit mass and unit charge moves with velocity `vecv=(8hati+6hatj)ms^-1` in magnetic field of `vecB=2hatkT`. Choose the correct alternative (s).A. The path of the particle may be `x^2+y^2-4x-21=0`B. The path of the particle may be `x^2+y^2=25`C. The path of the particle may be `y^2+z^2=25`D. The time period of the particle will be 3.14 s |
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Answer» Correct Answer - A::B::D `r=(mV)/(Bq)=((1)(10))/((2)(1))=5m` `T=(2pim)/(Bq)=((2)(pi)(1))/((2)(1))=pi` `=3.14s` Plane of circle is perpendicular to `B`, i.e., `xy`-plane. |
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