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A deutron of kinetic energy `50` keV is describing a circular orbit of radius `0.5` meter in a plane perpendicular to magnetic field `vecB`. The kinetic energy of the proton that describes a circular orbit of radius `0.5` meter in the same plane with the same `vecB` isA. 25 keVB. 50 keVC. 200 keVD. 100 keV |
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Answer» Correct Answer - D |
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