A diamond weighs `3.71 g`. It is put into a box weighing `1.4 kg`. Find the total weight of the box and diamond to the correct number of significant figures.

A diamond weighs `3.71 g`. It is put into a box weighing `1.4 kg`. Fin

1.	A diamond weighs `3.71 g`. It is put into a box weighing `1.4 kg`. Find the total weight of the box and diamond to the correct number of significant figures.
Answer» Correct Answer - `~ 1.4 kg` `3.17 g = 0.00371 = 1.40371 kg ~ 1.4 kg` [ correct up to one place of decimal]

Discussion

No Comment Found

Related InterviewSolutions

Using the expression `2d sin theta = lambda`, one calculates the values of `d` by measuring the corresponding angles `theta` in the range `0 to [email protected]`. The wavelength `lambda` is exactly known and error in `theta` is constant for all values of `theta`. As `theta` increases from `[email protected]`A. the absolute error in `d` remains constant.B. the absolute error in `d` increases.C. the fractional error in `d` remain constant.D. the fractional error in `d` decreases.
Using the expression `2d sin theta = lambda`, one calculates the values of `d` by measuring the corresponding angles `theta` in the range `0 to [email protected]`. The wavelength `lambda` is exactly known and error in `theta` is constant for all values of `theta`. As `theta` increases from `[email protected]`A. the absolute error in `d` remains constant.B. the absolute error in `d` increases.C. the fractional error in `d` remain constant.D. the fractional error in `d` decreases.
A wire of length `l = +- 0.06cm` and radius `r =0.5+-0.005 cm` and mass `m = +-0.003gm`. Maximum percentage error in density isA. `4`B. `2`C. `1`D. `6.8`
If `x and a` stand for distance , then for what value of `n` is the given equation dimensionally correct? The equation is `int (dx)/( sqrt ( a^(2) - x^(n))) = sin^(-1) (x)/(a)`A. `0`B. `2`C. `-2`D. `1`
Test dimensionally if the `v^2=u^2+2ax` may be correct.
Check whether the relation `S = ut + (1)/(2) at^(2)` is dimensionally correct or not , where symbols have their usual meaning .
If `E , M , J , and G` , respectively , denote energy , mass , angular momentum , and gravitational constant , then `EJ^(2) //M^(5) G^(2)` has the dimensions ofA. TimeB. AngleC. MassD. Length
If `L and R` denote inductance and resistance , respectively , then the dimensions of `L//R` areA. ` M^(1) L^(0) T^(0) Q^(-1)`B. ` M^(0) L^(0) T Q^(0)`C. ` M^(0) L^(1) T^(-1) Q^(0)`D. ` M^(-1) L T^(0) Q^(-1)`
Find the dimensions of capacitance.A. `[M^(-1) L^(-2) T A^(2)]`B. `[M^(-1) L^(-2) T^(3) A^(2)]`C. `[M^(-1) L^(-2) T^(4) A^(2)]`D. `[M^(-1) L^(-2) T^(2) A^(2)]`
Which of the following pairs have the same dimensions ? (L = inductance , C = capacitance , R = resistance)A. `(L)/( R ) and CR`B. ` LR and CR`C. `(L)/( R) and sqrt(L C)`D. `R C and (1)/( L C )`

A diamond weighs `3.71 g`. It is put into a box weighing `1.4 kg`. Find the total weight of the box and diamond to the correct number of significant figures.

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment