A dice is thrown once, find the probability of:(i) getting an even num

1.	A dice is thrown once, find the probability of:(i) getting an even number.(ii) getting a number larger than 3.(iii)A number between 3 and 6.
Answer» Tossing the die all possible outcomes = 1, 2, 3, 4, 5, 6 ∴ Total number of all possible outcomes =6 (i) The even digits are 2, 4, 6 ∴ The number of favourable outcomes = 3 ∴ Required probability = \(\frac { 3 }{ 6 }\) = \(\frac { 1 }{ 2 }\) (ii) The digits more than 3 are 4, 5, 6 ∴ The number of favourable outcomes = 3. ∴ Requred probability = \(\frac { 3 }{ 6 }\) = \(\frac { 1 }{ 2 }\) (iii) The digit between 3 and 6 are 4 and 5. ∴ The number of favourable outcomes = 2 ∴ Required probability = \(\frac { 2 }{ 6 }\) = \(\frac { 1 }{ 3 }\)

A dice is thrown once, find the probability of:(i) getting an even number.(ii) getting a number larger than 3.(iii)A number between 3 and 6.

Answer»

Tossing the die all possible outcomes

= 1, 2, 3, 4, 5, 6

∴ Total number of all possible outcomes =6

(i) The even digits are 2, 4, 6

∴ The number of favourable outcomes = 3

∴ Required probability = \(\frac { 3 }{ 6 }\) = \(\frac { 1 }{ 2 }\)

(ii) The digits more than 3 are 4, 5, 6

∴ The number of favourable outcomes = 3.

∴ Requred probability = \(\frac { 3 }{ 6 }\) = \(\frac { 1 }{ 2 }\)

(iii) The digit between 3 and 6 are 4 and 5.

∴ The number of favourable outcomes = 2

∴ Required probability = \(\frac { 2 }{ 6 }\) = \(\frac { 1 }{ 3 }\)

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