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A die is thrown 6 times. If ‘getting an odd number’ is a success, what is the probability of: at most successes? |
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Answer» P(X ≤ 5) = P(0) + P(1) + P(2) + P(3) + P(4) + P(5) = [1 + 6 + 15 + 20 + 15 + 6] = 63/64 |
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