A die is thrown. Find the probability of getting a prime number

1.	A die is thrown. Find the probability of getting a prime number
Answer» We know that, Probability of occurrence of an event = \(\frac{Total\,no.of\,Desired\,outcomes}{Total\,no.of\,outcomes}\) As 2, 3, 5 are prime numbers up to 6, so the desired outcomes are 2, 3, 5, and total outcomes are 1, 2, 3, 4, 5, 6 Therefore, total no. of outcomes are 6, and total no. of desired outcomes are 3 Probability of getting a prime number = \(\frac{3}{6}\) = \(\frac{1}{2}\) Conclusion: Probability of getting a prime number when a die is thrown is \(\frac{1}{2}\)

Answer»

We know that,

Probability of occurrence of an event

= \(\frac{Total\,no.of\,Desired\,outcomes}{Total\,no.of\,outcomes}\)

As 2, 3, 5 are prime numbers up to 6, so the desired outcomes are 2, 3, 5, and total outcomes are 1, 2, 3, 4, 5, 6

Therefore, total no. of outcomes are 6, and total no. of desired outcomes are 3

Probability of getting a prime number

= \(\frac{3}{6}\)

= \(\frac{1}{2}\)

Conclusion: Probability of getting a prime number when a die is thrown is \(\frac{1}{2}\)

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A die is thrown. Find the probability of getting a prime number

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