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A die is thrown. Find the probability of getting (i) a prime number, (ii) a number greater than or equal to 3. |
Answer» Let S be the sample when a die is thrown. Then S = {1, 2, 3, 4, 5, 6}, n(S) = 6 Let A be the event of getting a prime number. A = {2, 3, 5}, n(A) = 3 Let B be the event of getting a number greater than or equal to 3. B = {3, 4, 5, 6}, n(B) = 4 (i) P(a prime number) = \(\frac{n(A)}{n(S)}=\frac{3}{6}=\frac{1}{2}\) (ii) P(a number ≥ 3) = \(\frac{n(B)}{n(S)}=\frac{4}{6}=\frac{2}{3}\) |
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