A die is thrown, Find the probability of(i) prime number (ii) multiple

1.	A die is thrown, Find the probability of(i) prime number (ii) multiple of 2 or 3 (iii) a number greater than 3
Answer» In a single throw of die any one of six numbers 1,2,3,4,5,6 can be obtained. Therefore, the tome number of elementary events associated with the random experiment of throwing a die is 6. (i) Let A denote the event “Getting a prime no”. Clearly, event A occurs if any one of 2,3,5 comes as out come. So, Favorable number of elementary events = 3 Hence, P (Getting a prime no.) =3/6=1/2 (ii) An multiple of 2 or 3 is obtained if we obtain one of the numbers 2,3,4,6 as out comes So, Favorable number of elementary events = 4 Hence, P (Getting multiple of 2 or 3) =4/6=2/3 (iii) The event “Getting a number greater than 3” will occur, if we obtain one of number 4,5,6 as an out come. So, Favorable number of out comes = 3 Hence, required probability =3/6=1/2

A die is thrown, Find the probability of(i) prime number (ii) multiple of 2 or 3 (iii) a number greater than 3

Answer»

In a single throw of die any one of six numbers 1,2,3,4,5,6 can be obtained. Therefore, the tome number of elementary events associated with the random experiment of throwing a die is 6.

(i) Let A denote the event “Getting a prime no”. Clearly, event A occurs if any one of 2,3,5 comes as out come.

So, Favorable number of elementary events = 3

Hence, P (Getting a prime no.) =3/6=1/2

(ii) An multiple of 2 or 3 is obtained if we obtain one of the numbers 2,3,4,6 as out comes

So, Favorable number of elementary events = 4

Hence, P (Getting multiple of 2 or 3) =4/6=2/3

(iii) The event “Getting a number greater than 3” will occur, if we obtain one of number 4,5,6 as an out come.

So, Favorable number of out comes = 3

Hence, required probability =3/6=1/2

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