1.

A die is thrown once. Find the probability of getting an even prime number.

Answer»

A die is thrown once. 

Therefore, possible outcomes are {1, 2, 3, 4, 5, 6}. 

Hence, total possible outcomes = n(S) = 6. 

Let the event E be the event of getting an even prime number. 

Since, only even prime number is 2. 

Therefore, number of outcomes favourable to event E is n(E) = 1

Hence, the probability of getting an even prime number = \(\frac{n(E)}{n(s)} = \frac{1}{6}\)



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