Saved Bookmarks
| 1. |
A die is thrown once. Find the probability of getting an even prime number. |
|
Answer» A die is thrown once. Therefore, possible outcomes are {1, 2, 3, 4, 5, 6}. Hence, total possible outcomes = n(S) = 6. Let the event E be the event of getting an even prime number. Since, only even prime number is 2. Therefore, number of outcomes favourable to event E is n(E) = 1 Hence, the probability of getting an even prime number = \(\frac{n(E)}{n(s)} = \frac{1}{6}\) |
|