A die is thrown once. Find the probability of getting (i) a prime num

1.	A die is thrown once. Find the probability of getting (i) a prime number; (ii) a number lying between 2 and 6; (iii) an odd number.
Answer» i) When a die is thrown for one time, total number of outcomes = 6 No. of outcomes favourable to a prime number (2, 3, 5) = 3 ∴ Probability of getting a prime = \(=\frac{No.\,of\,favourable\,outcomes}{Total\,no.\,of\,outcomes}\) = 3/6 =1/2 ii) No. of outcomes favourable to a number lying between 2 and 6 (3, 4, 5) = 3 ∴ Probability of getting a number between 2 and 6 \(=\frac{No.\,of\,favourable\,outcomes}{Total\,no.\,of\,outcomes}\) = 3/6 =1/2 iii) Number of outcomes favourable to an odd number (1, 3, 5) = 3 ∴ Probability of getting an odd number P(odd) \(=\frac{No.\,of\,favourable\,outcomes}{Total\,no.\,of\,outcomes}\) = 3/6 =1/2

A die is thrown once. Find the probability of getting (i) a prime number; (ii) a number lying between 2 and 6; (iii) an odd number.

Answer»

i) When a die is thrown for one time, total number of outcomes = 6

No. of outcomes favourable to a prime number (2, 3, 5) = 3

∴ Probability of getting a prime =

\(=\frac{No.\,of\,favourable\,outcomes}{Total\,no.\,of\,outcomes}\)

= 3/6

=1/2

ii) No. of outcomes favourable to a number lying between 2 and 6 (3, 4, 5) = 3

∴ Probability of getting a number between 2 and 6

\(=\frac{No.\,of\,favourable\,outcomes}{Total\,no.\,of\,outcomes}\)

= 3/6

=1/2

iii) Number of outcomes favourable to an odd number (1, 3, 5) = 3

∴ Probability of getting an odd number P(odd)

\(=\frac{No.\,of\,favourable\,outcomes}{Total\,no.\,of\,outcomes}\)

= 3/6

=1/2

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