

InterviewSolution
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A die thrown. Find the probability of getting:(i) a prime number(ii) 2 or 4(iii) a multiple of 2 or 3 |
Answer» (i) Outcomes of a die are: 1, 2, 3, 4, 5, 5 and 6 Total number of outcome = 6 Prime numbers are: 1, 3 and 5 Total number of prime numbers = 3 Probability of getting a prime number = Total prime numbers/Total number of outcomes = 3/6 = 1/2 ∴ Probability of getting a prime number = 1/2 (ii) Outcomes of a die are: 1, 2, 3, 4, 5, 5 and 6 Total number of outcome = 6 Probability of getting 2 and 4 is Total numbers/Total number of outcomes = 2/6 = 1/3 ∴ Probability of getting 2 and 4 is 1/3 (iii) Outcomes of a die are: 1, 2, 3, 4, 5, 5 and 6 Multiples of 2 and 3 are = 2, 3, 4 and 6 Total number of multiples are 4 Probability of getting a multiple of 2 or 3 is Total numbers/Total number of outcomes = 4/6 = 2/3 ∴ Probability of getting a multiple of 2 or 3 is 2/3 |
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