A dielectric slab of dielectric constant k=5 is placed between plates of parallel plate capacitor, thickness of slab is 30% of plate spacing & its area is same as that of the plates, new capacitance is C′ & old capacitance was C. The ratio C′C is approximately equal to

A dielectric slab of dielectric constant k=5 is placed between plates

1.	A dielectric slab of dielectric constant k=5 is placed between plates of parallel plate capacitor, thickness of slab is 30% of plate spacing & its area is same as that of the plates, new capacitance is C′ & old capacitance was C. The ratio C′C is approximately equal to
Answer» A dielectric slab of dielectric constant $k = 5$ is placed between plates of parallel plate capacitor, thickness of slab is $30$ % of plate spacing & its area is same as that of the plates, new capacitance is $C^{'}$ & old capacitance was $C$ . The ratio $\frac{C^{'}}{C}$ is approximately equal to

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A dielectric slab of dielectric constant k=5 is placed between plates of parallel plate capacitor, thickness of slab is 30% of plate spacing &amp; its area is same as that of the plates, new capacitance is C′ &amp; old capacitance was C. The ratio C′C is approximately equal to

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A dielectric slab of dielectric constant k=5 is placed between plates of parallel plate capacitor, thickness of slab is 30% of plate spacing & its area is same as that of the plates, new capacitance is C′ & old capacitance was C. The ratio C′C is approximately equal to