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A diet is to contain at least 80 units of vitamin A and 100 units of minerals. Two foods F_(1) and F_(2) are available. Food F_(1) costs Rs. 4 per unit food and F_(2) costs Rs. 6 per unit. One unit of food F_(1) contains 3units of vitamin A and 4 units of minerals. One unit of food F_(2) contains 6 units of vitamin A and 3 units of minerals. Formulate this as a linear programming problem. Find the minimum cost for diet that consists of mixture of these two foods and also meets the minimal nutritional requirements.

Answer»


Answer :The MINIMUM VALUE of Z = 4x + 6Y is Rs. 104. A diet CONTAINS 24 units of food `F_(1)"a nd "4/3` unit of food `F_(2)`.


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