1.

A differentiable function f defined for all x > 0 and satisfies f(x^2)=x^3 for all x > 0. What is the value f'(16) ?

Answer»

SOLUTION :`F(x^2)=x^3rArrf(x^2). 2x=3X^2rArrf(x^2)=(3x)/2rArrf(4^2)=(3xx4)/2rArrf(16)=6`


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