Saved Bookmarks
| 1. |
A differentiable function f defined for all x > 0 and satisfies f(x^2)=x^3 for all x > 0. What is the value f'(16) ? |
| Answer» SOLUTION :`F(x^2)=x^3rArrf(x^2). 2x=3X^2rArrf(x^2)=(3x)/2rArrf(4^2)=(3xx4)/2rArrf(16)=6` | |