A diode is connected to `220V (rms)` `ac` in series with a capacitor as shown in fig. The voltage across the capacitor is A. `220 V`B. `110 V`C. `311.1 V`D. `220/(sqrt(2))V`

A diode is connected to `220V (rms)` `ac` in series with a capacitor a

1.	A diode is connected to `220V (rms)` `ac` in series with a capacitor as shown in fig. The voltage across the capacitor is A. `220 V`B. `110 V`C. `311.1 V`D. `220/(sqrt(2))V`
Answer» Correct Answer - D The diode `D` will conductor for positive half cycle of a.c. supply because this is forward biased. For negative half cycle of `a.c.` supply, this is reverse biased and does not conduct. So output would be half wave rectified output `V_(rms)=(V_(0))/2=(200sqrt(2))/2=200/(sqrt(2))`

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A diode is connected to `220V (rms)` `ac` in series with a capacitor as shown in fig. The voltage across the capacitor is A. `220 V`B. `110 V`C. `311.1 V`D. `220/(sqrt(2))V`

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