InterviewSolution
Saved Bookmarks
| 1. |
A diople consisting of an electron and a proton separated by a distance of `4xx10^(-10)` m is situated in an electric field of intensity `3xx10^(5) NC^(-1)` at an angle of `30^(@)` with the field. Calculate the diople moment and the torque acting on it. Charge e on an electron `= 1*6xx10^(-19) C.` |
|
Answer» Here, `q = 1*6xx10^(-19) C,` `2a = 4xx10^(-10) m, E = 3xx10^(5) NC^(-1), theta = 30^(@)` `p = qxx2a = 1.6xx10^(-19)xx4xx10^(-10) ` `= 6*4xx10^(-29) Cm` `tau = pE sin theta = 6*44xx10^(-29)xx3xx10^(5)xxsin 30^(@)` `= 9*6xx10^(-24) Nm` |
|